Question

A car starts from rest if its acceleration is 1.5 metre per second square in 1.5 seconds then calculate the distance travelled by it​

Answer 1

Using 2nd Equation of motion
S=ut +1/2 at^2
u=0( as car has started from rest) a=1.5m/s^2 t=1.5s
S=1/2*1.5*(1.5)^2
S=1/2* 3.375
S=1.68m

Answer 2

Explanation:

$During \: rest , u = 0$

$a = 1.5 m/sec²$

$t = 1.5 seconds$

$S = ut + \frac{1}{2}at²$

$S = 0*1.5 + \frac{1}{2} × 1.5 × (1.5)²$

$S = 0 + \frac{1}{2} × (1.5)³$

$S = \frac{(1.5)³}{2}$

$S =\frac{3.375}{2}$

$S = \frac{3375}{2000}$

$S =\frac{1687.5}{1000}$

$S = 1.6875 \: meter$

$S = 1.7 \: meter(लगभग)$