Physics, asked by vardan8252, 5 hours ago

A car starts from rest . if its acceleration is 1.5m/s^2 in 1.5 seconds, then calculate the distance travelled by it

answer the question with correct explanation. your answer is 168.75. give the answer with correct explanation.​

Answers

Answered by singhk61687
2

Answer:

Answer

Correct option is

A

52 m

During first 4s the distance traveled, x

1

=ut+at

2

/2=0+

2

1×16

=8m

At the end of these 4s it will gain velocity v=at=1×4=4m/s

So the new distance in next 10sec with constant velocity v

is x

2

=v×10=40m

and then it comes to rest after travelling a distance s with retardation a

1

so this s=

2a

1

v

2

=

2×2

16

=4m

Total distance is d=x

1

+x

2

+s=8+40+4=52m answer

Answered by patilsanjay3735
0

Answer:

त्या वेळी मी तुला काय वाटते हे मी तुला तू त्या काळी शाई नाही

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