Question

a car starts from rest it acquires a speed of 25ms after 20s the distance moved by the car during this time is

Answer 1

speed =distance/time

25=dis./20

distance=25×20=500ms

Answer 2

Given that,

Initial speed, u = 0

Final speed, v = 25 m/s

Time, t = 20 s

To find,

The distance moved by the car.

Solution,

Firstly, finding the acceleration of the car as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{25}{20}\\\\a=1.25\ m/s^2$

Let d is the distance moved by the car during this time. Using second equation of motion to find it as :

$d=ut+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1.25\times (20)^2\\\\d=250\ m$

So, the distance moved by the car during this time is 250 meters.

Learn more,

Kinematics

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