Question

A car starts from rest. Its speed at t = 5s is 25 m/s. Find the distance travelled by it after 10s.
(a)125m
(b)250m
(c)300m
(d)325m​

Answer 1

distance= s*t

==>25*10

===>250 m

opt-b

Answer 2

GiVen:

• A car starts from rest.
• Its speed at t = 5s is 25 m/s.

To find:

• The distance travelled by it after 10s.

Solution:

• Let u be 0 m/s as it starts from rest.

Here,

• V = 25 m/s
• u = 0 m/s

• Let's calculate acceleration.

⠀⠀━━━━━━━━━━━━━━━━━━━━

« Now, By using first equation of motion,

As we know that,

• V = u + at

→ 25 = 0 + a × 5

→ a = 25/5

→ a = 5 m/s²

∴ Hence, Acceleration is 5 m/s².

⠀⠀━━━━━━━━━━━━━━━━━━━━

« Now, By using second equation of motion,

As we know that,

• S = ut + 1/2 at²

→ S = 0 × 10 + 1/2 × 5 × 10²

→ S = 0 + 50 × 5

→ S = 250m

∴ Hence, Distance travelled by the car is 250 m.