Question

A car starts from rest. Its velocity reaches to 36km/hr in 5seconds. Find its acceleration and distance traveled by it.(4)

Answer 1

Answer:

• Acceleration = 2m/s²
• Distance covered = 50m

Explanation:

Given,

A car starts from rest and attains a velocity of 36km/h in 5 sec.

Converting the velocity into m/s :-

→ 36 ÷ 3.6

→ 10m/s

Acceleration is given by :-

$\sf \longrightarrow \: a = \dfrac{(v - u)}{t}$

Where,

• v(final velocity) = 10m/s
• u(initial velocity) = 0m/s [Since, it was at rest]
• t(time) = 5 sec.

From the given parameters,

$\sf \longrightarrow \: a = \dfrac{(10 - 0)}{5}$

$\sf \longrightarrow \: a = \dfrac{10}{5}$

$\sf \longrightarrow \: a = 2m/s^2$

∴ The car accelerated by 2m/s²

And also, calculating the distance travelled :-

→ Distance = speed × time

→ 10 × 5

→ 50m

∴ Distance travelled by the car is 50m

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