Question

a car starts from rest moves with acceleration 3m/s2.find distance travelled in 12th second?

Answer 1

Given:-

• Initial velocity,u = 0m/s

• Acceleration ,a = 3m/s²

• Time taken ,t = 12 s

To Find:-

• Distance covered ,s

Solution:-

We have to calculate the distance travelled by the car .

Using 2nd equation of motion

• S = ut + 1/2at²

Substitute the value we get

→ S = 0×12 + 1/2× 3×12²

→ S = 0 + 1/2 × 3 × 144

→ S = 3 × 72

→ S = 216 m

Therefore, the distance covered by the car is 216 metres.

Additional Information!!

Some equation of motion are

• v = u +at

• S = ut +1/2at².

• v² = u² + 2as

Here,

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement or Distance

t is the time taken

Answer 2

$\huge{\boxed{\sf{\red{Question}}}}$

A car starts from rest moves with acceleration 3m/s2.find distance travelled in 12th second?

$\huge{\boxed{\sf{\red{Answer}}}}$

${\bigstar}\large{\boxed{\sf{\pink{Given \: that}}}}$

• Acceleration = 3 m/s²
• Time taken = 12 seconds
• Initial velocity = 0 m/s

${\bigstar}\large{\boxed{\sf{\pink{To \: find}}}}$

• Distance travelled in 12 seconds.

${\bigstar}\large{\boxed{\sf{\pink{Solution}}}}$

$\large\green{\texttt{By using 2nd motion's equation}}$

$\large\blue{\texttt{Formula to solve this problem}}$

$\bold{\orange{\fbox{\orange{S = ut + 1/2 at²}}}}$

$\large{\texttt{Substituting the value we get}}$

➝ S = 0 × 12 + 1/2 × 3 × 12²

➝ S = 0 + 1/2 × 3 × 144

{ We get 144 bcz 12² = 144 ( 12 ×12 ) = 144 } { ² means square }

➝ 3 × 72

➝ 216 metres.

↝ Hence, 216 metres is the answer.

↝ 216 m is distance travelled in 12th second.

@Itzbeautyqueen23

Hope it's helpful.

Thank you :)