Question

A car starts from rest on a curve of radius 100 m and accelerates at constant tangential
acceleration at 3 m/sw. The normal component of acceleration at t=10s is____ m/s2.

Options
1)3
2)6
3)9
4)0
​

Answer 1

Answer:

6 is the answer dude. I don't know how but it's 6.

Answer 2

Given:

A car starts from rest on a curve of radius 100 m and accelerates at constant tangential

acceleration at 3 m/s².

To find:

Value of normal component of acceleration at t=10 secs.

Calculation:

Velocity at that time be v:

Applying 1st equation of kinematics:

$\therefore \: v = u + at$

$\implies \: v = 0 + (3 \times 10)$

$\implies \: v = 30 \: m {s}^{ - 1}$

Now, normal component of acceleration means the centripetal acceleration experienced by the object.

$\therefore \: a_{c} = \dfrac{ {v}^{2} }{r}$

$\implies\: a_{c} = \dfrac{ {(30)}^{2} }{100}$

$\implies\: a_{c} = \dfrac{ 900}{100}$

$\implies\: a_{c} = 9 \: m {s}^{ - 2}$

So, centripetal acceleration is 9 m/s².