Question

A car starts from rest on a highway accelerates in a straight line at a constant rate 4 m/s2 for 10 sec. How far does the car travel during this time? Calculate its final velocity.

Answer 1

Answer:

The equation for problems of this sort is as follows:

distance = (1/2)(a)(t^2)

distance = (1/2)(3.0 m/sec^2) x (8.0 sec^2)

distance = 96 meters

You can also think about it this way. With constant acceleration, the average velocity will occur at the midpoint of the time or (1/2)(8.0 sec)(3.0 m/sec^2) or 12 m/sec.

Then 12 m/sec x 8.0 sec = 96 meters

Explanation:

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