Question

A car starts from rest with a constant acceleration of 6 m/s. find
The velocity after 10 s. b) the displacement in 10 s.​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Final\:velocity=60\:m/s}}}$

$\green{\tt{\therefore{Displacement=300\:m}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Acceleration(a) =6 { \: m/s}^{2} \\ \\ \tt: \implies Time(t) = 10 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Final \: velocity =? \\ \\ \tt: \implies Displacement =?$

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \tt: \implies v = 0 + 6 \times 10 \\ \\ \green{\tt: \implies v = 60 { \: m/s}} \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies s = ut + \frac{1}{2} {at}^{2} \\ \\ \tt: \implies s =0 \times 10 + \frac{1}{2} \times 6 \times {10}^{2} \\ \\ \tt: \implies s =3 \times 100 \\ \\ \green{\tt: \implies s = 300 \: m}$

Answer 2

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✰Question ✰

⋄ A car starts from rest with a constant acceleration of 6 m/s.

Find :-

(a) The velocity after 10 s.

b) The displacement in 10 s.

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❍ Given :-

⋄ Initial velocity of car (u) =0m/s

⋄ Acceleration of car (a) =6m/s

⋄ Time taken (t) =10s

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❍ To Find :-

⋄ Final velocity (v) of car after 10s.

⋄ Displacement of car (s) in 10 s.

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❍ Solution :-

Final Velocity after 10s.

By using 1st equation of motion

v=u+at

v= 0+6×10

v = 60m/s.

∴ The final velocity of car after 10s is 60m/s

And Now,

Displacement of car in 10s

By using 2nd equation of motion

s=ut + 1/2at²

s = 0×10+1/2×6×10×10

s=300m

∴The displacement of car after 10s is 300m.