Science, asked by hancykto3762, 1 year ago

A car starts from rest with a uniform acceleration of 4 ms–2. The distance travelled in metres at the ends of 1s, 2s, 3s and 4s are respectively,(a) 4, 8, 16, 32 (b) 2, 8, 18, 32
(c) 2, 6, 10, 14 (d) 4, 16, 32, 64

Answers

Answered by jitumahi89
4

Answer:

Option (c) 2, 6, 10, 14 is correct.

Explanation:

Since we have the formula for the distance traveled by the body in nth second.

S_{n} = u + \frac{a(2n-1)}{2}.................................(1)

Here object is at rest so , u = 0 m/s and acceleration (a) = 4 m/s^2

For 1 s

S_{1} = 0 + \frac{4(2-1)}{2} = 2 metre

For 2 s

S_{2} = 0 + \frac{4(4-1)}{2} = 6 metre

For 3 s

S_{3} = 0 + \frac{4(6-1)}{2} = 10 metre

For 4 s

S_{4} = 0 + \frac{4(8-1)}{2} = 14 metre

So, option (c) 2, 6, 10, 14 is correct.

Answered by krishpanchal2014
0

Answer:

Option (c) 2, 6, 10, 14 is correct.

Explanation:

Since we have the formula for the distance traveled by the body in nth second.

.................................(1)

Here object is at rest so , u = 0 m/s and acceleration (a) = 4 m/s^2

For 1 s

= 2 metre

For 2 s

= 6 metre

For 3 s

= 10 metre

For 4 s

= 14 metre

So, option (c) 2, 6, 10, 14 is correct.

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