Question

a car starts from the rest. After 40 seconds ,the velocity of the car becomes 40 m/s.calculate the acceleration of the car

Answer 1

$\huge{\underline{\sf{\blue{Given-}}}}$

Initial velocity u= 0m/s

Final velocity v= 40m/s

Time t= 40sec

$\huge{\underline{\tt{\orange{FIND-}}}}$

acceleration-?

Formula to be used=>

$\boxed{a = \dfrac{v-u}{t}}$

$\huge{\underline{\tt{\red{Solution-}}}}$

$a= \dfrac{40-0}{40}$

$a=1 m/s^2$

Hope helpful :)

Answer 2

$\star \: \displaystyle \large\underline{\mathtt{ \green{ Question:}}}$

• A car starts from the rest. After 40 seconds ,the velocity of the car becomes 40 m/s.calculate the acceleration of the car?

$\star \: \displaystyle \large \underline{\mathtt{ \green{ Given}}}$

• initial velocity = 0 m/s
• time taken = 40 seconds
• final velocity = 40 m /s

$\star \: \displaystyle \large \underline{\mathtt{ \green{To \: find :}}}$

• acceleration of the car

$\star \: \displaystyle \large \underline{\mathtt{ \green{ Solution:}}}$

By using the first kinematic equation ,

$\bigstar \boxed{ \mathtt{ \pink{v = u + at}}}$

here,

• v= final velocity
• u = initial velocity
• a = acceleration
• t = time

Substituting the given values in the above equation we get ,

$\displaystyle \rightarrow \mathtt{v = at}$

$\displaystyle \rightarrow \mathtt{a = \frac{v}{t} }$

$\displaystyle \rightarrow \mathtt{a = \frac{40}{40} }$

$\displaystyle \rightarrow \boxed{ \red{\mathtt{a = 1 \frac{m}{ {s}^{2} } }}}$