Question

a car starts from the rest and travels with an uniform acceleration. The car travels 100 m in 5s what will be it's final velocity?​

Answer 1

Given:-

• Initial Velocity of Car = 0m/s

• Distance travelled = 100m

• Time taken = 5s

To Find:-

• The Final Velocity of car.

Formulae used:-

• s = ut + ½ × a × t²

• v² - u² = 2as

Where,

• s = Distance
• u = Initial Velocity
• a = Acceleration
• t = Time
• v = Final velocity

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Now,

→ s = ut + ½ × a × t²

→ 100 = 0 × 5 + ½ × a × (5)²

→ 100 = 0 + ½ × a × 25

→ 100 × 2 = 25a

→ 200 = 25a

→ a = 8m/s²

Hence, The Acceleration of car is 8m/s²

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Therefore,

→ v² - u² = 2as

→ v² - (0)² = 2 × 8 × 100

→ v² = 1600

→ √v² = √1600

→ v = 40m/s

Hence, The final Velocity of car is 40m/s.

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Answer 2

GiveN :

• Initial velocity (u) = 0 m/s
• Distance Travelled (s) = 100 m
• Time (t) = 5s

To FinD :

• Final Velocity

SolutioN :

Apply second equation of Kinematics :

⇒s = ut + ½ at²

⇒100 = 0 + ½ * a * 5²

⇒(100 * 2)/25 = a

⇒a = 8 m/s²

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Now, Applying First equation of Kinematics :

⇒v = u + at

⇒v = 0 + 8 * 5

⇒v = 40 m/s