Question

A car starts from the state of rest, moves with a uniform acceleration for 6 seconds and attains a velocity of 36m/s

a) What is the initial velocity of the car

b) Find the acceleration of the car​

Answer 1

Answer:

Vi = 2(d/t)-Vf

=2(6m/6s)-36m/s

= 2m/s - 36 m/s

= - 34m/s

A = v/t

= 36m/s divided by 6s

= 6m

Explanation:

not sure po yan hehe

Answer 2

Answer :-

Given :-

Initial velocity = 0 m/s

Final velocity = 36 m/s

Time taken = 6 sec

To find :-

Acceleration - a

Solution :-

The car is at rest, hence the Initial velocity of a car = 0

Initial velocity = 0 m/s

Calculating Acceleration :-

• u = 0 m/s
• v = 36 m/s
• t = 6 sec

Substituting the value in 1st equation of motion :-

⟹ v = u + at

⟹ 36 = 0 + 6a

⟹ 6a = 36

⟹ a = 36/6

⟹ a = 6 m/s²

Acceleration = 6 m/s²