Question

A car starts its journey from P and reaches R through the path as shown in the figure. If a = 1 m, b= 6 m and r=7 m. The ratio of distance to the
magnitude of displacement of the car will be take == 22/7)
0 1:1
0 73:21
0 29:27
0 73:49
​

Answer 1

Answer :

A car starts its journey from P and reaches T through the path as shown in the figure.

We have to find the ratio of distance to the displacement$.$

★ Distance is defined as the total length of actual path which is covered by the moving object.

• It is a scalar quantity.

Let's calculate distance covered by the car.

$\leadsto\sf\:d=a+\pi(r)+b+\pi(2r)$

$\leadsto\sf\:d=1+\dfrac{22}{7}(7)+6+\dfrac{22}{7}(2\times 7)$

$\leadsto\sf\:d= 1+22+6+44$

$\leadsto\bf\:d=73m$

★ Displacement is defined as the shortest distance between initial and final position of the entire journey.

• It is a vector quantity.

$\leadsto\sf\:d'=a+2r+b+4r$

$\leadsto\sf\:d'=1+2(7)+6+4(7)$

$\leadsto\sf\:d'=1+14+6+28$

$\leadsto\bf\:d'=49m$

By taking the ratio, we get

➝ d/d' = 73/49

➝ d : d' = 73 : 49