Question

A car starts its journey with the initial speed of 20 m/s and stops for 10 seconds.Find its retardation.​

Answer 1

Answer:

Retardation= -2m/s^2

Explanation:

u=20m/s , v=0m/s , t=10sec

a=?

a=(v-u)/t

a=(0-20)/10

a= -2 m/s^2

Answer 2

Answer:

2m/s^2

Explanation:

u=20m/s

t=10s

v=0m/s [ATQ it will eventually come to rest]

⇒ -a=$\frac{v-u}{t}$

-a=0-20 / 10

-a=-20/10

-a= -2   [minus sign will cancel out]

∴a=2 m/$s^{2}$

Pls mark brainliest