Question

a car starts its motion from rest and gets 30m/s velocity in 12 sec calculate acceleration of the car (2)distance covered in meters (3) velocity after 7sec
please pleaseis question ka answer full explain krke dena mera exam h merko bhoot jruri cahiye
​

Answer 1

Explanation:

s=u×t+21×a×t2         -------(1)

a=tv−u             -------(2)

where  s is Distance travelled.

            u is initial Speed.

            v is final Speed.

            a is Acceleration.

             t is time.

Given : u=0,v=30sm,t=6sec

            a=630                        using equ. (2)

            a=5s2m          

            s=0+21×5×62     using equ. (1)

             s=90m