Question

a car starts moving from rest and attains a velocity of 10m/s in 5 minutes . If the acceleration is constant, then calculate :
(a) acceleration
(b) distance travelled by the car

please give answer​

Answer 1

Correct question:-

A car starts from rest and attains a velocity of 10m/s in 5 minutes. If the acceleration is constant,then calculate:

(a)acceleration

(b)distance travelled by the car

Given:-

→Initial velocity of the car=0

→Final velocity of the car=10m/s

→Time taken=5 mins

To find:-

→Acceleration of the car

→Distance travelled by the car

Solution:-

Firstly,let's convert the time from minute to second.

=>1 min=60s

=>5min=5(60)

=>300s

By using the 1st equation of motion,we get:-

=>v=u+at

=>a=v-u/t

=>a=10-0/300

=>a=10/300

=>a=1/30 m/s²

Now,by using the 2nd equation of motion,we get:-

=>s=ut+1/2at²

=>s=0×300+1/2×1/30×(300)²

=>s=90000/60

=>s=1500m

Thus:-

→Acceleration of the car is 1/30 m/s².

→Distance travelled by the car is 1500m.