Question

A car starts moving from rest and attains a velocity of 10m/s in 5

minutes. If the acceleration is constant, Then calculate:

a)acceleration b)Distance travelled by the car​

Answer 1

• a. 0.033 m/s²
• b. 1500 m

GIVEN:

• Initial velocity, u = 0 m/s

• Final velocity, v = 10 m/s

• Time, t = 5 minutes.

TO FIND:

• Acceleration, a

• Distance travelled by the car, s

FORMULAE:

• According to first equation of motion, v = u + at

• According to second equation of motion , s = ut + (at²)/2

SOLUTION:

STEP 1: TO CONVERT TIME IN STANDARD UNIT:

• The standard unit of time is second.

• 1 minute = 60 seconds

• 5 minutes = 5 × 60 seconds

• Time, t = 300 sec

STEP 2: TO FIND ACCELERATION:

v = u + at

10 = 0+ 300 a

10 = 300 a

a = 10/300

Acceleration, a = 0.033 m/s²

STEP 3 : TO FIND DISTANCE TRAVELLED:

$s = ut +  \dfrac{1}{2} a{t}^{2}  \\\\ s = (0 \times 300) +  (\frac{1}{2}  \times 0.033 \times  {300}^{2} ) \\\\ s = 0 + (  \frac{1}{2}  \times  \dfrac{10}{300}  \times 300 \times 300) \\\\  =  \dfrac{1}{2}  \times 10 \times 300 \\  \\  = 5 \times 300 \\\\ distance \: s = 1500 \: m$

ANSWER:

• Acceleration of the car is 0.033 m/s²

• Distance travelled by the car is 1500 m.

OTHER FORMULAE:

• First equation of motion, v = u + at

• Second equation of motion , s = ut + (at²)/2

• Third equation of motion , v²- u² =  2as

• All the three equations of motion is applicable only when acceleration is constant.

• Here acceleration is constant and does not change with time. Hence constant acceleration is independent of time.

Answer 2

Answer:

I hope it's help OK

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