Question

a car starts moving from rest under uniform acceleration 0.5m/s² what will be the velocity after covering a distance of 100m​

Answer 1

Answer:

10m/s

Explanation:

u=0 (from rest)

a=0.5 m/s^2

s=100m

v=?

From 3rd equation of motion,

v^2= u^2 + 2as

v^2 = 0 + 2×0.5×100

= 100

v = 10m/s

Answer 2

Answer:

$\bigstar{\bold{Final\:velocity=10\:m/s}}$

Explanation:

$\Large{\underline{\underline{\it{Given:}}}}$

• Initial velocity (u) = 0 m/s
• Acceleration (a) = 0.5 m/s²
• Distance travelled (s) = 100 m

$\Large{\underline{\underline{\it{To\:Find:}}}}$

• Final velocity (v)

$\Large{\underline{\underline{\it{Solution:}}}}$

→ Here we have to find the velocity of the car after it has travelled a distance of 100 m.

→ By the third equation of motion, we know that

 v² - u² = 2as

→ Substituting the datas we get,

  v² - 0² = 2 × 0.5 × 100

  v² = 1 × 100

  v² = 100

  v = √100

  v = 10 m/s

→ Hence the velocity of the car is 10 m/s.

$\boxed{\bold{Final\:velocity=10\:m/s}}$

$\Large{\underline{\underline{\it{Notes:}}}}$

→ The three equations of motion are :

• v = u + at
• s = ut + 1/2 × a × t²
• v² - u² = 2as