Question

A car starts moving on a linear path with initial velocity 2 m/s and after 10 seconds its velocity becomes 12 m/s then the distance travelled in 10 second will be?
[ans:- 70m] please explain...​

Answer 1

Answer:

An object is moving with constant acceleration. Its velocity is 48m s

−1

at the end of 10 second and becomes 68m s

−1

at the end of the 15 second. What would be the distance travelled by the object in 15 second?

Answer 2

Answer:

Distance travelled in 10 second will be 70m

Explanation:

$Initail velocity(u) = 2 m/s\\\\Final Velocity (v) = 12 m/s\\\\time(t) = 10 sec$

$Acceleration = \frac{Change in velocity}{Time}$

$Acceleration = \frac{12-2}{10}\\ a = 1 m/s^{2}$

$Dist travelled (s) = ut + 0.5at^{2} \\\\s = 2*10 + 0.5*10*10\\\\s = 20 + 50\\\\s= 70 m$