A car starts moving with an acceleration 5 m/s for 10 sec then it decelerates with 2m/s find the total distance travelled by the car till it stop
Answers
Answered by
24
Answer:
The total distance traveled= 625+250
=875m
Explanation:
Let us first calculate the velocity achieved by the car at the end of 10s
v=u+at
as u=0 v=50m/s
distance traveled at the end of first 10 sec= s= at²÷2= 5×100÷2= 250m
Time taken for the car to go to rest that is v=0, u=50 a=-2
v=u+at
t=u÷a=25s
Distance travelled= 2×a×s =v²-u²
2×2×s=2500
s=2500÷4
s=625
The total distance traveled= 625+250
=875m
Similar questions