Question

a car starts rest.it accelerates at a rate of 12m/s².what is the velocity of a car at the end of 3.0 second?​

Answer 1

Answer:

V=u+at. (u=0)

V=12×3=36m/s

Answer 2

Question:

A car starts rest. It accelerates at a rate of 12m/s². What is the velocity of a car at the end of 3.0 second?​

Answer:

s = ut + ½at^2 …. (1)  

v^2 = u^2 + 2as …. (2)  

v = u + at …. (3)  

s = (u + v)t/2 …. (4)  

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.  

In this case, we know u = 0, a = 12m/s^2, t = 3s and we want to find v, so we use equation (3)  

v = u + at  

v = 0 + 12(3) = 36m/s  

The velocity after 3s is 36m/s.

Explanation:

Hope this answer will help you.