Question

A car starts starts from rest and moves with uniform acceleration

a.at the same instant from the same point a bike crosses with a uniform velocity u. when and where will they meet ? what is the velocity of car with respect to the bike at the time of meeting

Answer 1

the speed of the car is 2 times the speed of the bike at the point of meeting

Answer 2

Answer:

Step-by-step explanation:

let car and bike meet 'd' from starting point each other and after time 't' they meet.

as car start from rest u = 0

so

s= ut +1/2 at²

2d = at² - - - -- - - 1

for bike is in uniform speed

so

distance = sppeed *time

d = u*t - - -- - - 2

from eq 1 and 2

2ut = at²

t = 2u / a

so distance

d = u* 2u/ a

= 2u² / a

so bike and car meet at 2u² / a diance after t = 2u / a time.