Question

a car starts with a initial velocity of 20m/s and acceleration 5m/s² . find the distance covered by it in 30 s​

Answer 1

Answer:

$175 \: \: ans$

Explanation:

u=20m/s

a=5m/s2

t=5s

S=?

as we know,

S=ut+1/2at2

=20×5+1/2(5)25

=100+150/2

=350/2

=175m

Answer 2

Answer:

• Distance travelled is 2,850 m.

Given:

• Initial velocity = 20 m/s
• Acceleration = 5 m/s²
• Time taken = 30 sec

Explanation:

$\rule{300}{1.5}$

Here, we are given that a car starts with the initial velocity of 20 m/s and accelerates at the rate of 5 m/s². We are asked to find out the distance travelled by the car in 30 sec.

From second kinematic equation we know,

$\longrightarrow{\sf{s\ =\ ut\ +\ \dfrac{1}{2}at^2}}$

Substitute the values,

$\longrightarrow{\sf{s\ =\ 20 \times 30\ +\ \dfrac{1}{2} \times 5 \times (30)^2}} \\ \\ \\ \longrightarrow{\sf{s\ =\ 600\ +\ \dfrac{1}{2} \times 5 \times 30 \times 30}} \\ \\ \\ \longrightarrow{\sf{s\ =\ 600\ +\ \dfrac{1}{2} \times 4,500}} \\ \\ \\ \longrightarrow{\sf{s\ =\ 600\ +\ \dfrac{1}{\cancel2} \times \cancel{4,500}}} \\ \\ \\ \longrightarrow{\sf{s\ =\ 600\ +\ 2,250}} \\ \\ \\ \longrightarrow{\sf{s\ =\ 2,850\ m}}$

∴ The distance travelled by the car is 2,850 m.

$\rule{300}{1.5}$