A car starts with a velocity of 10 metre second and accelerates at rate of 5 metre sec find the final velocity a distance 30m
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Answered by
1
hi friend,
given u=10m/s
a=5m/s²
s=30m
let v be the final velocity ...
we know that
v²=u²+2as
v²=10²+2(5)(30)
v²=100+300
v²=400
v=±20m/s
I hope this will help u:)
given u=10m/s
a=5m/s²
s=30m
let v be the final velocity ...
we know that
v²=u²+2as
v²=10²+2(5)(30)
v²=100+300
v²=400
v=±20m/s
I hope this will help u:)
Answered by
2
Hey friend !
hi friend,
Initial velocity = u=10 m/s
acceleration = a = 5 m/s²
distance covered = s = 30 m
final velocity = v
Equation of motion :-
v² = u² + 2 as
v² = 10² +2× 5 × 30
v² = 100 + 300
v² = 400
v = 20 m/s
hi friend,
Initial velocity = u=10 m/s
acceleration = a = 5 m/s²
distance covered = s = 30 m
final velocity = v
Equation of motion :-
v² = u² + 2 as
v² = 10² +2× 5 × 30
v² = 100 + 300
v² = 400
v = 20 m/s
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