Question

A car starts with the initial velocity of 10 metres per second and accelerated at a rate of 5 metre per second square .find the final velocity when the car has travelled a distance of 30 metre. What the timing has been taken by the car for this motion?​

Answer 1

hey dost!

Answer:

According to the given question,

u = initial velocity = 10 m/s

a = acceleration = 5 m/s^2

s = displacement = 30 m

v = final velocity and t = time

And we are asked to find final velocity and time.

Here displacement can be treated as distance, as it's a linear motion.

We know,

From the 3rd equation of motion,

v^2 = u^2 + 2as

Putting the values we get,

v^2 = 100 + 2×5×30

v^2 = 100 + 300

v^2 = 400

v = 20 m/s

(Talking velocity as positive as direction is linear means direction is not changing)

Again, From 1st equation of motion,

v = u+at

Putting the values we get,

20 = 10 + 5t

5t = 20-10

5t = 10

t = 10/5

t = 2 sec

Therefore, final velocity of the car is 20 m/s and time taken by the car is 2 sec from the given data.

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Sayonara !