A car starts with the initial velocity of 10 metres per second and accelerated at a rate of 5 metre per second square .find the final velocity when the car has travelled a distance of 30 metre. What the timing has been taken by the car for this motion?
Answers
hey dost!
Answer:
According to the given question,
u = initial velocity = 10 m/s
a = acceleration = 5 m/s^2
s = displacement = 30 m
v = final velocity and t = time
And we are asked to find final velocity and time.
Here displacement can be treated as distance, as it's a linear motion.
We know,
From the 3rd equation of motion,
v^2 = u^2 + 2as
Putting the values we get,
v^2 = 100 + 2×5×30
v^2 = 100 + 300
v^2 = 400
v = 20 m/s
(Talking velocity as positive as direction is linear means direction is not changing)
Again, From 1st equation of motion,
v = u+at
Putting the values we get,
20 = 10 + 5t
5t = 20-10
5t = 10
t = 10/5
t = 2 sec
Therefore, final velocity of the car is 20 m/s and time taken by the car is 2 sec from the given data.
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Sayonara !