Question

A car starts with velocity 20m/s and accelerate at rate 5m/s.Find the final velocity when the car has travelled a dstance of 40m.

Answer 1

Initial velocity (u) =20m/s
Acceleration (a) = 5m/s
Distance(s) = 40m
Let final velocity be v
Using third equation of motion
2as=v^2 -u^2
2 (5)(40) = v^2 -(20)^2
400 =v^2 -400
800 =v^2
v= 20√2
v= 20 (1.414)
= 28.28m/s

Answer 2

Hi there !

Initial velocity  = u  = 20m/s

Acceleration = a  = 5m/s

Distance = s  = 40m

Final velocity =  v

Equation of motion :-

2as = v² - u²

400 =  v² - 20²
400 = v² -400
800 = v²

v = √800
  = 28.28 m/s   [approx.]