Question

a car stopped after travelling distance 8m due to applying brakes at the speed of 40 m/s. Find acceleration & retordation of car in that period.(v²-u²= 2as)

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Answer 1

Answer:

(v^(2)-u^(2)=2as) Here u = 40 m/s, v = 0 (vehical stopped), s = 8m, a = ? Acceleration = 100m/s2 with retordation on (- sign).

Explanation:

Here u = 40 m/s, v = 0 (vehical stopped), s = 8m, a = ?

v2−u2=2as

0−402=2×a×8

a=−(40)(40) by 2×8=−100m/s2

Acceleration = 100m/s2 with retordation on (- sign).

Answer 2

Explanation:

2.5 metre per second square