Question

A car stopped after travelling the distance 8m due to applying brakes at the speed of 40m/s.Now find the acceleration and retardation of car in that period.(v2-u2=2as)​

Answer 1

Answer:

initial velocity (u) = 40 m/s

Final velocity ( V) = 0 m/s

Time taken ( T ) = 20 second

now first we find the retardation after then we find distance

V= u + at

or, a =( V- u)/T

or a = -40/20

or a = - 2 m/s²

now V² = u² + 2as

or S = - (40)²/ 2 (-2)

or S = 400 m

hence distance coveres before come to rest is 400 m.