A car stopped at traffic lights and then drove off with constant acceleration of 2 m/s². What is the speed of the car after 8 seconds?
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Answered by
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Explanation:
a=2
t=8
u=0
v²-u²=2as
v²-0²=2x2xs
v²=4s
v=2√s.......1
s=ut+1/2at²
s=0t+.5x2x8x8
s=64
putting the value of 's' in 1
v=2√64
v=2x8
v=16m/s
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