Question

A car takes 1 hour less to cover a distance of 200 km if its speed is increased by 10 km/hr, than its usual speed. What is the usual speed of the car?

Answer 1

$let \: \: usual \: \: speed \: \: be \: \: x \\ \frac{200}{x + 10} = \frac{200}{x} - 1 \\ \frac{200}{x + 10} = \frac{200 - x}{x} \\ 200x = (x + 10)(200 - x) \\ 200x = 190x - {x}^{2} + 2000 \\ {x}^{2} + 10x - 2000 = 0 \\ (x + 50)(x - 40) = 0 \\ x = - 50 \: \: or \: \: 40 \\ \\ since \: \: - ve \: \: value \: \: is \: \: not \: \: possible \\ usual \: \: speed = 40 \: \frac{km}{hr}$

Answer 2

Answer:

Step-by-step explanation:

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