Question

a car takes 2 hour to reach a destination at speed of 60 km per hour then time taken to reach the destination at speed of 80 kilometres per hour




it's Isha

gm to all​

Answer 1

≡hey Isha di....

≡ hru

≡mine all good:)

≡ here is your answer....

Consider the speed to be x and the time taken to be y.

If the speed increases, the time required to reach will decrease. Hence, they are in inverse proportion.

Two numbers x and y are said to be in inverse proportion when an increase in one quantity decreases the other quantity and vice versa.

xy = k or x = (1/y) k

where k is a constant.

Hence, x₁y₁ = x₂y₂

60 × 2 = 80 × y₂

y₂ = (60 × 2)/80

y₂ = 3/2

y₂ = 1.5 hours

Thus, 1.5 hours are required to reach the destination if the speed is increased to 80 km/hour

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Answer 2

Answer:

2 hour 40 minute

Step-by-step explanation:

$\large\underline{\sf{Solution \rightarrow}}$

$\large\underline{\sf{Given \rightarrow}}$

$\large\underline{\sf{➡2 \: hour \: is \: needed \: to \: travel \: 60km}}$

We need to find the time in which it will cover 80km per hour.

So if we notice the question the question is in direct proportion.

Before we start let's first understand what is direct proportion.

In direct proportion if one quantity increase(decrease) the other also increase(decrease).

So,the formula is:-

$\large{\sf{ \frac{ x_{1}}{x_{2}} = \frac{ y_{1} }{y_{2} } }}$

$\large\underline{\sf{✳ \frac{120min}{ x_{2}} = \frac{60km}{80km} ✳ }}$

As it is directly proportional

On cross multiplying we get,

$\large\underline{\sf{ \implies \frac{120 \times 80}{60} = x }}$

$\large\underline{\sf{ \implies 160min}}$

$\large\underline{\sf{(60 + 60 + 40)min}}$

$\large\underline{\sf{2 \: hr \: 40 \: min}}$

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