.A car takes 7 hours to cover a certain distance at the speed of 48 km/h. If the speed is decreased by
20 km/h, how much time will it take to cover the same distance?
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Given data:-
- A car takes 7 hours to cover a certain distance at the speed of 48 km/hr.
- The speed is decreased by 20 km/hr.
Here
- Speed of car = 48 km/hr
- Time = 7 hour
Solution:-
{According to given}
Now, we use fromula of speed:-
—› Speed of car = {Distance}/{Time}
—› 48 = {Distance}/7 i.e.
—› Distance = 48 × 7
—› Distance = 336 km ..... ( 1 )
Speed is decreased by 20 km/hr from 48 km/hr. hence,
—› Speed of car = {48 - 20}km/hr
—› Speed of car = 28 km/hr ....( 2 )
Now, we use fromula of speed:-
—› Speed of car = {Distance}/{Time}
{from eq. ( 1 ) & eq. ( 2 )}
—› 28 = 336/{Time} i.e.
—› Time = 336/28
—› Time = 12 hour
Hence, car take 12 hour to cover 336 km with speed 28 km/hr.
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