Question

a car tavelling at 9ms-1 accelerate and attain a speed of 27ms-1 in5s. calculate the acceleration and the distance covered in 5s

Answer 1

U=9 m/s
V=27m/s
T=5s
By first law of motion
V=u+at
27=9+a*5
5a=27-9
A=18/5
A=3.6answer
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