A car that runs 40 kilometers per hour, puts a brake and stops it in 2 meters, if the speed of the car is 80 kilometers per hour, then how many distance will it stop
pradyumnaproudindian:
time taken to stop
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In the first scenario,
u= 40km/hr
S=2m= 0.002km.
v=0 ( As the vehicle comes to rest)
Using the Formula


2a= -1600/0.002
a= -400000 km/hr^2
using this 'a' solving for the second scenario,
u=80 km/hr
v=0
0= 80^2 - 2(400000)S
S= 6400/800000
S= 8 meters.
Hope this helps.
u= 40km/hr
S=2m= 0.002km.
v=0 ( As the vehicle comes to rest)
Using the Formula
2a= -1600/0.002
a= -400000 km/hr^2
using this 'a' solving for the second scenario,
u=80 km/hr
v=0
0= 80^2 - 2(400000)S
S= 6400/800000
S= 8 meters.
Hope this helps.
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