Question

A car that's initially traveling at 10 m/s acceleration uniformly for 4 seconds at a rate of 2 m/s?in a straight line. How far does the car travel during this time?
a. 56m
b. 62m
C. 72 m
d. 86m
e.NOT​

Answer 1

Answer:

u=10

t=4

a=2

s=?

Explanation:

s=ut+1/2at²

s=(10×4)+(1/2×2×4×4)

s=40+16

s=56m

so final answer is 56m

Answer 2

Given :

Initial velocity = 10m/s

Time taken = 4 sec

Acceleration = 2m/s²

To find :

The distance covered by the car

Solution :

As we are provided with initial velocity, acceleration and time we can use second law of Kenimatics that is,

$\boxed{ \bf s = ut + \dfrac{1}{2} {at}^{2} }$

where,

• s denotes distance covered
• u denotes initial velocity
• t denotes time
• a denotes acceleration

substituting all the given values in the equation,

$\leadsto{ \sf s = ut + \dfrac{1}{2} {at}^{2} }$

$\leadsto{ \sf s = (10)(4) + \dfrac{1}{2} {(2)(4)}^{2} }$

$\leadsto{ \sf s = 40 + 16}$

$\leadsto{ \sf s = 56 \: m }$

thus, the distance covered by the car is 56m.

Hence, Option (a) 56m is correct.