A car took 500 seconds to move from point A to B and 900 seconds to move from B to A. If the distance between A and B is 2100 m, then what is the average speed of this car?
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12
Distance from A to B=2100m
Thus,total distance covered=2×2100=4200m
Total time taken=(500+900)s=1400s
Average speed=total distance/total time
4200/1400
3m/s
Answered by
1
Answer:
Distance from a to b is = 2100×2
Time taken = 500+900
Speed = Distance/Time
= 4200/1400
= 3m/s... Answer..
Explanation:
Because the car travels 2 times from point A to B.
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