A car trains a velocity of 36km/h after accerlating uniformly from rest in 5sec find the distance travelled
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v= 36 km/hr = (36× 1000) / 3600 = 10 m/sec
u= 0 (rest)
t=5 sec
from 1st eq of motion
v= u+at
10 = 0 + a× 5
10 = 5a
a= 10/ 5
a= 2 m/s²
from 3rd eq of motion
v² = u²+ 2as
(10)² = 0 + 2× 2×s
100 = 4s
s= 100 / 4
s= 25 m
u= 0 (rest)
t=5 sec
from 1st eq of motion
v= u+at
10 = 0 + a× 5
10 = 5a
a= 10/ 5
a= 2 m/s²
from 3rd eq of motion
v² = u²+ 2as
(10)² = 0 + 2× 2×s
100 = 4s
s= 100 / 4
s= 25 m
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