Question

A car travel a distance 100m with a constant acceleration and average velocity of 20ms-1 . The final velocity acquired by the car is 25ms-1. Find:the inital velocity 2. Acceleration of car

Answer 1

Average Speed = Distance Covered/Elapsed Time

Therefore,20=100/Elapsed Time

Elapsed Time=100/20=5 sec

Also,

Average Velocity=Initial Velocity(u)+Final Velocity(v)

                                                      2                              

Substituting The given Values,

20=(u+25)/2......v Is Given As 25m/s

Therefore, u= 40-25=15m/s

Acceleration(a)=(v-u)/t= (25-15)/5 =10/5 =2m/s^2

Answer 2

Required Answer :

As per the provided information in the given question, we have :

Distance covered, s = 100 m

Average velocity, $\overline{\nu}$ = 20 m/s

Final velocity, v = 25 m/s

We've been asked to calculate the initial velocity and acceleration of the car.

As we know that, average velocity is given by :

⇒ $\boxed{\sf{ \overline{\nu} = \dfrac{v + u}{2} }}$

v denotes final velocity

u denotes initial velocity

$\overline{\nu}$ denotes average velocity

⇒ $\overline{\nu}$ = (u + 25)/2

⇒ 20 = (u + 25)/2

⇒ 20 × 2 = u + 25

⇒ 40 = u + 25

⇒ 40 ― 25 = u

⇒ 15 m/s = u

Therefore, initial velocity of the car is 15 m/s.

Now, we need to calculate the acceleration of the car. By using the third equation of motion,

⇒ v² — u² = 2as

v denotes final velocity

u denotes initial velocity

a denotes acceleration

s denotes distance

⇒ (25)² — (15)² = 2 × a × 100

⇒ 625 ― 225 = 200a

⇒ 400 = 200a

⇒ 400 ÷ 200 = a

⇒ 2 m/s² = a

Therefore, acceleration of the car is 2 m/s².