A car travel at a speed of 60 km/hr for 0.52,at 30 km/hr for the next 0.24h and then at 70 km/hr for the next 0.71h .what is the average speed of the car?
Answers
Hmm ... This problem can be solved by taking the harmonic mean off all three of the speed .... I think the question is wrong as units are not given correctly...
Answer:
Time for which the train moved at the first speed = 0.52 h
The first distance = Speed × Time
= 60 × 0.52 = 31.2 km
Second speed = 30 km/h
Time for which the train moved at the second speed = 0.24 h
The second distance = Speed × Time
= 30 × 0.24 = 7.2 km
Third speed = 70 km/h
Time for which the train moved at the third speed = 0.71 h
The third distance = Speed × Time
= 70 × 0.71 = 49.7 km
The total distance travelled = 31.2 km + 7.2 km + 49.7 km = 88.1 km
Total time taken = 0.52 h + 0.24 h + 0.71 h = 1.47 h
Now, Average speed = Total distance traveled/ Total time taken
or, Average speed = 88.1/1.47 ≈ 59.93 km/h
Therefore, the average speed of the train is 59.93 km/h.
.
.
.
.
.
.
thanks for.. mera itna sara answer dene ke liye.