Math, asked by arvind2001lko, 9 months ago

A car travel first 60 km at speed of 3v km/hr and travel next 60 km at 2v km/hr. What is the average speed of the car?

Answers

Answered by abdul9838

2

$<b> <body \: bgcolor = "yellow">$

Here is Answer

Solution

From case first

Distance (d1)=60 km

Speed(v1)=3v km/h

Let time be t1

Therefore

$\bf \red{t1 = \frac{distane}{speed} } \\ \\ \bf \red{t1 = \frac{ \cancel60}{ \cancel3v} } \: \\ \\ \bf \red{t1 = \frac{20}{v} } \\ \\$

Now

From case 2nd

Distance(d2)=60 km

Speed(v2)=2v km/h

Let the time be t2

Therefore

$\bf \red{t2 = \frac{distance(d2)}{speed(v2)} } \\ \\ \bf \red{t2 = \frac{ \cancel60}{ \cancel2v} } \\ \\ \bf \red{t2 = \frac{30}{v} } \\ \\ \bf \red{average \: speed = \frac{total \: distance}{total \: time} } \\ \\ \bf \red{average \: speed = \frac{d1 + d2}{t1 + t2} } \\ \\ \bf \red{average \: speed = \frac{60 + 60}{ \frac{20}{v} + \frac{30}{v} } } \\ \\ \bf \red{ average \: speed = \frac{ 120}{ \frac{20 + 30}{v} } } \\ \\ \bf \red{ average \: speed = \frac{12 \cancel0v}{5 \cancel0} } \\ \\ \bf \red{average \: speed = \frac{12}{5}v } \\ \\ \bf \red{ \boxed{ \bf \: average \: speed{ = 2.4 \: v} \: km \: per \: h}}$

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