Question

a car travel with uniform velocity of 20m/s .the driver applies breaks and the car comes to rest in 10sec. calculate the retardation​

Answer 1

using first equation of motion

v=u+at

the final velocity becomes zero

then

0=20+10a

thus, a=-2m/s^2

Answer 2

Answer:

-2 m/s^2

Explanation:

u = 20, v = 0, t = 10

Acceleration = v - u / t

= 0-20 / 10

= -20 / 10

= -2 m/s^2