Question

A car travela three fourth of the distance at the speed of 25 kmph the remaining diatance of the speed at 10 kmph .what is the average speed of the entire journey

Answer 1

Step-by-step explanation:

Let the total distance be x km.

Then car travels (3/4)x km with a speed of 25 km/h,

so time taken during this journey,t1= ((x(3/4))/25) hr = (3x/100) hr.

remaining distance = ( x - (3x/4)) = (x/4) km ,

car travels this remaining distance with a speed of 10 km/h,

time taken during this journey, t2= ((x/4)/10) hr = (x/40) hr.

total time, T = t1 + t2 = (3x/100) + (x/40) = (11x/200) hr

avg speed of total journey = ( total distance / total time taken )

= (x/(11x/200)) = (200/11) = 18.18 km/h