Question

A car traveling at 22.5 m/s skids to a stop in 25 s. Determine the skidding distance of the car

Answer 1

Answer:

U = 22.4 m/s

v = 0

t = 2.55 s

v = u+at

0 = 22.4+a*2.55

-22.4 = 2.55 a

-22.4/2.55 = a

8.784 = a

a = 8.784 m/s²

Explanation:

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Answer 2

Answer:

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