Question

a car traveling at 25 m/ s accelerated to 30 m/s into 2 seconds. Find rate of acceleration and distance covered. ​

Answer 1

Acceleration by the car

$= \frac{v - u}{t} = \frac{5}{2} \: m {s}^{ - 2}$

Then, distance travelled = ut + 1/2 at^2

= 50 + 5

= 55 m

HOPE THIS COULD HELP!!!