A car traveling at 36 km/h speed up 72 km/h in sec what is its accelartion if the same car stop in 20 sec what is its retardation
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in first case to find acceleration we have
u = 36km/h = 10m/s
v = 72km/h = 20m/s
t = 1s
we know ,
a = (v - u) / t
= (20 - 10)m/s / 1s
= 10m/s^2
in second case to find retardation we have
u = 20m/s
v = 0m/s
t = 20s
we know,
a = (v - u) /t
= (0 - 20)m/s / 20s
= -1m/s^2
hope it will help you..........
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