A car traveling at 60km/hr uniformly retards for 10sec and reaches at a velocity of 36 km. Find its retardation
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initial velocity (u)=60
final velocity (v)=36
time=10sec
accel.=(v-u)/t
=(36-60)/10=-24/10=-24
retardation =2.4m/sec square
final velocity (v)=36
time=10sec
accel.=(v-u)/t
=(36-60)/10=-24/10=-24
retardation =2.4m/sec square
Answered by
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Hi. .
a = (v-u)/t
Final velocity = 36km/hr
Initial velocity = 60km/hr
Therefore acceleration,
= (36-60)10
= (-24)/10
= - 2•4
Therefore acceleration is -2•4
Since the value is in negative, it must be retardation.
Hence retardation is 2•4 km/hr^2.
Hope this helps u!!
a = (v-u)/t
Final velocity = 36km/hr
Initial velocity = 60km/hr
Therefore acceleration,
= (36-60)10
= (-24)/10
= - 2•4
Therefore acceleration is -2•4
Since the value is in negative, it must be retardation.
Hence retardation is 2•4 km/hr^2.
Hope this helps u!!
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