Question

A car traveling at 9m per second and attains a speed of 27m per second in 5seconds . Calculate the acceleration and distance covered in 5 seconds.

Answer 1

Explanation:

initial speed u=9m/s

final speed v=27m/s

time t=5 secs

v=u+at

a=3.6m/sec square

$s = ut + \frac{1}{2} at {}^{2}$

s=(9*5)+(0.5*3 .6*5*5)=90 metres