Question

a car traveling at 9m/s accelerate and attain a speed of 27m/s in 5 sec. calculate the acceleration and distance covered in 5 sec

Answer 1

Answer:

a=3.6m/s² ,s=90m

Explanation:

a=(v-u)÷t

therefore, a is 3.6 m/s²

and ,

s=ut+(1/2)at²

s is 90 m

Answer 2

Answer:- u=9m/s

v=27m/s

t=5s

a=?

s=?

Now,

a=v-u/t

a=27m/s-5m/s/5s

a=15m/s/5s

a=3m/s^2

Now,

s=ut+1/2at^2

S=9×5+1/2×3×5^2

s=45+37.5

s=82.5m