Question

A car traveling at a speed of 10m/s is brought to rest in 20secs by applying breaks. Calculate the acceleration and d distance travelled during ths time.

Answer 1

Hey Chika ❤

Here's ur answer-

Given,
s or u = 10m/s
t = 20sec
v = 0m/s

To find,
a = ?
d = ?

We know that,

Case I
$\underline{speed \: = distance \div time}$
$10ms {}^{ - 1} = d \: \div 20 \\ d \: = 10 \times 20 \\ d \: = 200m$
Case II
$\underline{a = v - u \div t}$
$a = 0 - 10 \div 20 \\ a = - 10 \div 20 \\ a = -0.5ms {}^{ - 2}$

Hope it helps ✔